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X=-11.25+.25X^2
We move all terms to the left:
X-(-11.25+.25X^2)=0
We get rid of parentheses
-.25X^2+X+11.25=0
We add all the numbers together, and all the variables
-0.25X^2+X+11.25=0
a = -0.25; b = 1; c = +11.25;
Δ = b2-4ac
Δ = 12-4·(-0.25)·11.25
Δ = 12.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{12.25}}{2*-0.25}=\frac{-1-\sqrt{12.25}}{-0.5} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{12.25}}{2*-0.25}=\frac{-1+\sqrt{12.25}}{-0.5} $
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